How to Continue User Imput Ava

Java Program to Get Input from User

This article is created to cover multiple programs in Java that are based on receiving inputs from user. Here are the list of programs included in this article:

• Get integer input in Java
• Continue receiving inputs until user enters 0
• How to handle with invalid inputs in Java ?
• Get character input in Java
• Get string input in Java

Get Integer Input in Java

The question is, write a Java program to ask the user to enter an integer value and print the entered value back on the output screen. The program given below is its answer. This program basically shows, how to read an integer value in Java using Scanner and nextInt()

            import            java.util.Scanner;            public class            CodesCracker {            public static void            main(String[] args)    {            int            num;            Scanner            scan =            new            Scanner(System.in);            System.out.print("Enter an Integer Value: ");       num = scan.nextInt();            System.out.println("\nYou've entered: "            +num);    } }

The snapshot given below shows the sample run of above program, with user input 20:

You can use following methods, to scan values of other types:

• nextDouble() - to read value of double data type
• nextFloat() - to read value of float type
• nextLong() - to read value of long type
• nextShort() - to read value of short type
• nextByte() - to read value of byte type

Continue Receiving Integer Input until User enters 0 in Java

This program is created in a way, to continue receiving the inputs from user, until enters 0. You can modify this program, to use in a way, like to continue receiving inputs from user, until user enters a character 'x' or whatever you want.

            import            java.util.Scanner;            public class            CodesCracker {            public static void            main(String[] args)    {            Scanner            scan =            new            Scanner(System.in);            System.out.print("Enter an Integer Value: ");            int            num = scan.nextInt();            while(num!=0)          num = scan.nextInt();            System.out.println("\nProgram Closed!");    } }

Here is its sample run with some user inputs:

How to Handle with Invalid Inputs in Java ?

Now the question is, what if user enters an invalid input ?
Like when we need to get integer input, but user enters some other type of value such as a floating-point input, character input, or string input. Let's check it out with first program of this article, using another sample run, but with non-integer value say c, a character input, this time:

Now we need to put the scanner statement inside the try block, so that, we can catch that exception using the catch block. Here is the complete version of the code, created after modifying the first program of this article. This program handles with invalid input:

            import            java.util.Scanner;            import            java.util.InputMismatchException;            public class            CodesCracker {            public static void            main(String[] args)    {            int            num;            Scanner            scan =            new            Scanner(System.in);            System.out.print("Enter an Integer Value: ");            try            {          num = scan.nextInt();            System.out.println("\nYou've entered: "            +num);       }            catch(InputMismatchException            ime)       {            System.out.println("\nInvalid Input!");       }    } }

Here is its sample run with same user input as of previous sample run, that is c:

In above program, the following two statements:

            import            java.util.Scanner;            import            java.util.InputMismatchException;

can also be replaced with a single statement given below:

Take Character Input in Java

This program is created to show you, how the character input can be received from user at run-time of the program.

            import            java.util.Scanner;            public class            CodesCracker {            public static void            main(String[] args)    {            Scanner            scan =            new            Scanner(System.in);            System.out.print("Enter a Character: ");            char            ch = scan.next().charAt(0);            System.out.println("\nYou've entered: "            +ch);    } }

The sample run with user input Y is shown in the snapshot given below:

In above program, the next() method is used to receive string input, whereas the charAt() method is used to get the character available at any particular index specified using its parameter. Therefore, charAt(0) scans the very first character or the character available at 0^th index of the string. Therefore, if you enter any string like codescracker on the sample run of above program, then the first character, that is c will get initialized to ch. Here is its sample run with user input codescracker:

Get String Input from User in Java

To get string input from user in Java, we have following two methods:

• next()
• nextLine()

The next() method is used to scan a single word, name, or any string without space(s). Whereas the nextLine() method is used, when we need to scan and receive the whole string with or without spaces, typed before pressing the ENTER key. Let's create the program for both the methods.

Get String Input in Java - Without Space

This program uses next() method to scan a word or string without spaces.

            import            java.util.Scanner;            public class            CodesCracker {            public static void            main(String[] args)    {            Scanner            scan =            new            Scanner(System.in);            System.out.print("Enter a String: ");            String            str = scan.next();            System.out.println("\nYou've entered: "            +str);    } }

Here is its sample run with user input codescracker:

Here is another sample run with user input codescracker dot com:

Get String Input in Java - With Spaces

To receive the complete string with spaces, typed in a line, use nextLine() instead of next(). Rest of all the codes remains same as of previous program.

Here is its sample run, when you use nextLine(), while receiving the string input from user:

Get Multiple Inputs from User in Java

This is the last program of this article, created to show you, how you can get multiple inputs in Java language.

            import            java.util.Scanner;            public class            CodesCracker {            public static void            main(String[] args)    {            Scanner            scan =            new            Scanner(System.in);            System.out.print("How many numbers to enter ? ");            int            n = scan.nextInt();            int[] arr =            new            int[n];            System.out.print("Enter "            +n+            " Numbers: ");            for(int i=0; i<n; i++)          arr[i] = scan.nextInt();            System.out.println("\nYou've entered: ");            for(int i=0; i<n; i++)            System.out.print(arr[i]+            " ");    } }

Here is its sample run with user input 5 as size, and 23, 34, 45, 56, 67 as five numbers:

Same Program in Other Languages

• C Get Input from User
• C++ Get Input from User
• Python Get Input from User

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Source: https://codescracker.com/java/program/java-program-take-input-from-user.htm

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